JavaScript Set Logic
Logic MethodsIn JavaScript 2025, 7 new logical methods were added to the Set object: union()difference() intersection() isDisjointFrom() isSubsetOf() isSupersetOf() symmetricDifference() |
Browser Support
Set Logic is an ES2025 feature.
JavaScript 2025 is fully supported in all modern browsers since May 2025:
| Chrome 136 |
Edge 136 |
Firefox 129 |
Safari 18.2 |
Opera 120 |
| Apr 2025 | Apr 2025 | Aug 2024 | Des 2024 | May 2025 |
The union() Method
The union() method returns the union of two sets.
The union() method returns a new set containing the elements which are in this set,
or in the argument set, or in both:
Example
const A = new Set(['a','b','c']);
const B = new Set(['b','c','d']);
const C = A.union(B);
Try it Yourself »
The intersection() Method
The intersection() method returns the intersection of two sets.
The intersection() method returns a new set containing the elements which are in this set
and in the argument set:
Example
const A = new Set(['a','b','c']);
const B = new Set(['b','c','d']);
const C = A.intersection(B);
Try it Yourself »
The difference() Method
The difference() method returns the difference between two sets.
The difference() method returns a new set containing elements which are in this set
but not in the argument set:
Example
const A = new Set(['a','b','c']);
const B = new Set(['b','c','d']);
const C = A.difference(B);
Try it Yourself »
The symmetricDifference() Method
The symmetricDifference() method returns the symmetric difference between to sets.
The symmetricDifference() method returns a new set containing elements which are in this set
or in the argument set, but not in both:
Example
const A = new Set(['a','b','c']);
const B = new Set(['b','c','d']);
const C = A.symetricDifference(B);
Try it Yourself »
The isSubsetOf() Method
The isSubsetOf() method returns true if all elements in this set
is also elements in the argument set:
Example
const A = new Set(['a','b','c']);
const B = new Set(['b','c','d']);
let answer = A.isSubsetOf(B);
Try it Yourself »
The isSupersetOf() Method
The isSupersetOf() method returns true if all elements in the argument set are also in this set:
Example
const A = new Set(['a','b','c']);
const B = new Set(['b','c','d']);
let answer = A.isSupersetOf(B);
Try it Yourself »
The isDisjointFrom() Method
The isDisjointFrom() method returns true
if this set has no elements in common with the argument set:
Example
const A = new Set(['a','b','c']);
const B = new Set(['b','c','d']);
let answer = A.isDisjointFrom(B);
Try it Yourself »
